03-04-2017
Mathematics

contestada

What is the integral of sec x (sec x + tan x ) dx

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LammettHash LammettHash

03-04-2017

[tex]\sec x(\sec x+\tan x)=\sec^2x+\sec x\tan x[/tex]

Recall that [tex](\tan x)'=\sec^2x[/tex], and [tex](\sec x)'=\sec x\tan x[/tex].

So,

[tex]\displaystyle\int \sec x(\sec x+\tan x)\,\mathrm dx=\tan x+\sec x+C[/tex]

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